If chlorine bleach is mixed with other cleaning products containing ammonia, the toxic gas $\mathrm{NCl}_{3}(g)$ can form according to the equation $$3 \mathrm{NaClO}(a q)+\mathrm{NH}_{3}(a q) \longrightarrow 3 \mathrm{NaOH}(a q)+\mathrm{NCl}_{3}(g)$$
When $2.94 \mathrm{~g}$ of $\mathrm{NH}_{3}$ reacts with an excess of $\mathrm{NaClO}$ according to the preceding reaction, how many grams of $\mathrm{NCl}_{3}$ are formed?