If complex numbers $\mathrm{A}=\mathrm{a}+\mathrm{b} \omega+\mathrm{c} \omega^{2}, \mathrm{~B}=a \omega+\mathrm{b} \omega^{2}+\mathrm{c}$ and $\mathrm{C}=a \omega^{2}+\mathrm{b}+\mathrm{c} \omega$, represent the vertices of a triangle,
then the area of the triangle formed by $\mathrm{A}, \mathrm{B}, \mathrm{C}$ is, (where $\mathrm{r}$ is the radius of the circumcircle of the triangle)
(a) $\frac{3 \sqrt{3}}{4} \mathrm{r}^{2}$
(b) $\frac{\sqrt{3}}{4} \mathrm{r}^{2}$
(c) $\frac{2 \sqrt{3}}{4} \mathrm{r}^{2}$
(d) $\frac{3 \sqrt{3}}{2} \mathrm{r}^{2}$