Question
If $\cos \alpha+\cos \beta+\cos \gamma=\sin \alpha+\sin \beta+\sin \gamma=0$ then $\cos (\beta+\gamma)+\cos (\alpha+\beta)+\cos (\alpha+\gamma)$ is equal to(a) 1(b) 0(c) $-1$(d) $\frac{1}{2}$
Step 1
Step 1: Let's denote $A = \cos \alpha + i \sin \alpha$, $B = \cos \beta + i \sin \beta$, and $C = \cos \gamma + i \sin \gamma$. Show more…
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