Question
If $(\cos p-1) x^{2}+x \cos p+\sin p=0$ has real roots, the interval of possible values of $p$ is(a) $(-\pi, 0)$(b) $(0, \pi)$(c) $\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)$(d) $\left(0, \frac{3 \pi}{2}\right)$
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The equationshave at least one root on the interval Equations I. $\sin x-x+1=0$ II. $x^{2} / 4-\sin p x+\frac{2}{3}=0$ III. $x^{3} / 4-\sin p x+\frac{2}{3}=0$ IV. $2^{x}-3 x=0$ $$ \begin{aligned} &\hline \multicolumn{1}{c} {\text { Interval }} \\ &\hline \begin{array}{l} \text { (A) }(-2,1 / 2) \\ \text { (B) }(0,1) \\ \text { (C) }(0,3 \pi / 2) \\ \text { (D) }(-2,2) \\ \hline \end{array} \end{aligned} $$
If $\sin \frac{\mathrm{A}}{2}, \sin \frac{\mathrm{B}}{2}$ are the roots of $\mathrm{px}^{2}+\mathrm{qx}+\mathrm{r}=0,(\mathrm{p} \neq 0)$ and $\mathrm{A}=\frac{\pi}{3}$, (a) $\mathrm{p}+2 \mathrm{q}+4 \mathrm{r}=0$ (b) $p+q+r=0$ (c) $\mathrm{p}-2 \mathrm{q}+\mathrm{r}=0$ (d) $\mathrm{p}+2 \mathrm{q}=4 \mathrm{r}$
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