Question
If cube root of unity are $1, w, w^{2}$ then the roots of the equation $(\mathrm{x}-1)^{3}+8=0$ are(a) $-1,-1,-1$(b) $-1,-1+2 \mathrm{w},-1-2 \mathrm{w}^{2}$(c) $-1,1+2 \mathrm{w}, 1+2 \mathrm{w}^{2}$(d) $-1,1-2 \mathrm{w},+1-2 \mathrm{w}^{2}$
Step 1
We can rewrite this equation as $(x-1)^3 = -8$. Show more…
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