Question
If $E_{1}, E_{2}$ and $E_{3}$ are the kinetic energies of an electron, an $\alpha$ -particle and a proton, with same de-Broglie wavelength, then(a) $E_{1}>E_{3}>E_{2}$(b) $E_{2}>E_{3}>E_{1}$(c) $E_{1}>E_{2}>E_{3}$(d) $E_{1}=E_{2}=E_{3}$
Step 1
Step 1: The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{p}$, where $h$ is Planck's constant and $p$ is the momentum of the particle. Show more…
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