Question
If $f(-10 \sqrt{2})=2 \sqrt{2}$, then $f^{\prime \prime}(-10 \sqrt{2})$ is equal to(a) $\frac{4 \sqrt{2}}{7^{3} 3^{2}}$(b) $-\frac{4 \sqrt{2}}{7^{3} 3^{2}}$(c) $\frac{4 \sqrt{2}}{7^{3} 3}$(d) $-\frac{4 \sqrt{2}}{7^{\frac{1}{3}}}$
Step 1
Step 1: Given that $f(-10 \sqrt{2})=2 \sqrt{2}$, we can write the first equation as $3y^2 - 3x + 1 = 0$. Show more…
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If $f(-10 \sqrt{2})=2 \sqrt{2}$, then $f^{\prime \prime}(-10 \sqrt{2})=$ (a) $\frac{4 \sqrt{2}}{7^{3} 3^{2}}$ (b) $-\frac{4 \sqrt{2}}{7^{3} 3^{2}}$ (c) $\frac{4 \sqrt{2}}{7^{3} 3}$ (d) $-\frac{4 \sqrt{2}}{7^{3} 3}$
If $f(x)=\left(x^{2}+x+11\right) \sqrt{\left(x^{3}+5 x+121\right)},$ then $f^{\prime}(0)=$ (A) $\frac{5}{2}$ (B) $\frac{27}{2}$ (C) 22 (D) $\frac{247}{2}$
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