- A function $f$ is odd if $f(-x) = -f(x)$ for all $x$ in the domain.
Step 2:
First, let's determine if $f+g$ is even when both $f$ and $g$ are even functions.
We need to check if $(f+g)(-x) = (f+g)(x)$ for all $x$.
$(f+g)(-x) = f(-x) + g(-x)$
Since $f$ and $g$
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