if-f_ave-a-b-denotes-the-average-value-of-f-on-the-interval-a-b-and-a-c-b-show-that-f_ave-a-b-fracc-

Question

If $ f_{ave} [a, b] $ denotes the average value of $ f $ on the interval $ [a, b] $ and $ a < c < b $, show that
$$ f_{ave} [a, b] = \frac{c - a}{b - a} f_{ave} [a, c] + \frac{b - c}{b - a} f_{ave} [c, b] $$

Amrita Bhasin · Accepted Answer

we know the average value formula could be written with a beak, A, C and C B. Therefore, we know C minus a over B minus a times one over C minus A from a C. Kovacs detox is equivalent to one over B minus A from A to C of after box detox. And we know this can also be written as one over B minus a from sea to be after Rex detox. Given the fact that we are looking at the interval from A to B, we know we can write this as won over B minus A from A to B aftereffects. Detox is equivalent to the average value from A to B.

Problem 26 Hard Difficulty

If $ f_{ave} [a, b] $ denotes the average value of $ f $ on the interval $ [a, b] $ and $ a < c < b $, show that
$$ f_{ave} [a, b] = \frac{c - a}{b - a} f_{ave} [a, c] + \frac{b - c}{b - a} f_{ave} [c, b] $$

Answer

$f_{a v e}[a, b]$

Related Courses

Calculus: Early Transcendentals

Related Topics

Discussion

Top Calculus 2 / BC Educators

Catherine R.

Kayleah T.

Caleb E.

Michael J.

Calculus 2 / BC Courses

Integration Review - Intro

Definite vs Indefinite

Recommended Videos

Watch More Solved Questions in Chapter 6

Video Transcript