Question
if $\frac{1}{b-a}+\frac{1}{b-c}=\frac{1}{a}+\frac{1}{c}$, then $a, b, c$ are in(a) AP(b) $\mathrm{GP}$(c) HP(d) AGP
Step 1
Step 1: First, let's write down the given equation: \[\frac{1}{b-a}+\frac{1}{b-c}=\frac{1}{a}+\frac{1}{c}\] Show more…
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