If $f(x)=-\frac{1}{3} x^{3}+t^{2} x$, where $t$ is a real parameter. Let $m(t)$ denote the minimum of $\mathrm{f}(\mathrm{x})$ over $[0,1]$ then
(A) $m(t)=0$ if $t^{2} \geq \frac{1}{3}$
(B) $\mathrm{m}(\mathrm{t})=0$ for all $\mathrm{t}$
(C) $m(t)=t^{2}-\frac{1}{3}$ if $t^{2}<\frac{1}{3}$
(D) $\mathrm{m}(\mathrm{t})=\frac{1}{3}-\mathrm{t}^{2}$ for all $\mathrm{t}$.