00:01
Using the functions f of x and g of x, we need to evaluate the following.
00:05
So the first one, we're going to replace the g function with the letter a.
00:10
So this becomes a squared minus 1.
00:13
Then we're going to replace the f function with a squared minus 1.
00:18
So we have three times a squared minus 1 plus 4.
00:22
So this simplifies to be 3a squared minus 3 plus 4.
00:26
So this simplifies to be 3a squared plus 1.
00:31
So for the second one, we're going to evaluate the f function with a.
00:36
So we have 3 times a plus 4.
00:38
Then we're going to replace the g function with 3a plus 4 is equal to 3a plus 4 squared minus 1.
00:48
So this becomes 9a squared plus 24a plus 16 minus 1.
00:56
So this simplifies to be 9a squared plus 24a plus 15.
01:02
The third one, we're going to replace the g function into the f function, so f.
01:14
So we have three...