If $f(x)=\left\{\begin{array}{ll}3 x^{2}+12 x-1 ;-1 \leq x \leq 2 \\ 37-x & ; 2<x \leq 3\end{array}\right.$ then
(A) $\mathrm{f}(\mathrm{x})$ is increasing in $[-1,2]$
(B) $\mathrm{f}(\mathbf{x})$ is continuous in $[-1,3]$
(C) $f^{\prime}(2)$ does not exist
(D) $f(x)$ has the maximum value at $x=2$