Question
If $f(x)=\left\{\begin{array}{lll}-1: & x<0 \\ 0 & : & x=0 \text { and } g(x)=x\left(1-x^{2}\right) \\ 1 & : & x>0\end{array}\right.$then discuss the continuity of the function $h(x)$, where $h(x)=f(g(x))$.
Step 1
In the function $f(x)$, we replace $x$ with $g(x)$. This gives us: \[h(x) = \left\{\begin{array}{lll}-1: & g(x)<0 \\ 0 & : & g(x)=0 \\ 1 & : & g(x)>0\end{array}\right.\] Show more…
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