00:01
So for this problem, we're asked several things.
00:05
First thing we're asked to find is the domain of f.
00:10
So let's go ahead and look at that.
00:12
The thing about this function here is that we have the algebraic component of it and the denominator.
00:21
And when we do, just per fractions, we can't have the denominator equal to zero.
00:30
So therefore, this, when factored, is a difference of two squares.
00:35
So we have this and this that cannot equal zero.
00:41
So therefore, the domain for f for this first part is u cannot be 1 and negative 1.
00:52
Now, there are different ways of showing this.
00:56
One way to do this is with set notation.
01:00
And so you could say that this would be all you such that you cannot be negative.
01:13
One and one.
01:17
Okay, so that's one way to write that.
01:19
Another way to do it is with interval notation, so we could say that the domain is from negative infinity to negative one, union, negative one to one, union from infinity.
01:35
Just wanted to show all the different, two different ways here, just in case it's needed.
01:45
Okay, all right, so next part.
01:48
We want the domain of g of x, g equals ln of x here...