Question
If $f(x)=\log \left(\frac{x}{x-1}\right)$, show that,$f(x+1)+f(x)=\log \left(\frac{x+1}{x-1}\right)$
Step 1
We can do this by substituting $x+1$ into the function $f(x)$: \[f(x+1) = \log \left(\frac{x+1}{(x+1)-1}\right) = \log(x+1).\] Show more…
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