Question
If $f(x+y)=2 f(x) f(y), f^{\prime}(5)=1024(\log 2)$ and$f(2)=8$, then the value of $f(3)$ is(a) $64(\log 2)$(b) $128(\log 2)$(c) 256(d) $256(\log 2)$
Step 1
Now, we can plug in the given values for $f'(5)$ and $f(2)$: $1024(\log 2) = 2f'(5)f(2)$. Since $f(2) = 8$, we can substitute and solve for $f'(5)$: $1024(\log 2) = 2f'(5)(8)$. Dividing both sides by 16, we get: $f'(5) = 64(\log 2)$. Show more…
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