Question
If $G$ is a cyclic group and 15 divides the order of $G$, determine the number of solutions in $G$ of the equation $x^{15}=e$. If 20 divides the order of $G$, determine the number of solutions of $x^{20}=e$. Generalize.
Step 1
Since G is a cyclic group, there exists an element g in G such that the order of g is equal to the order of G. Let n be the order of G, so n is a multiple of 15. Then, we have: g^n = (g^15)^(n/15) = e Now, let's consider the elements x in G such that x^15 = e. Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 78 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let $G$ be an abelian group. Let $n$ be a fixed integer, and let $H=\left\{x \in G: x^{n}=e\right\}$. Prove that $H$ is a subgroup of $G$.
SUBGROUPS
C
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD