00:04
Okay, this is problem number 69, and it's a proof.
00:10
We're asked to prove that g of x is even, if and only if f of x is even, and also g of x is odd, if and only if f of x is odd, where g of x equals 1 over f of x.
00:25
Another way to think of that is g of x and f of x are reciprocal functions.
00:31
So to do this proof thoroughly and correctly, it's really quite a long process.
00:38
I'm not sure if your teacher or instructor is expecting you to do a purely theoretical mathematical proof, but i'm going to do it justice here and work through a pure mathematician's proof.
00:52
So in order to prove an if and only if statement, which is called a biconditional statement, which means it's going in both directions, we need to prove two things.
01:02
So i've broken it into part one and part 2.
01:06
We need to prove that if f of x is even, then g of x is even.
01:11
And we also need to prove that if g of x is even, then f of x is even.
01:16
And if we can prove both of those things, then we can conclude that g of x is even if and only if f of x is even.
01:25
Okay, so here we go through part one of the first of two proofs.
01:30
So buckle up.
01:32
This is going to be quite a ride.
01:34
So if f of x is even then g of x is even.
01:38
So our given is that f of x is even.
01:45
What does it mean for a function to be even? well, it means that opposite x values will have the same y value.
01:52
So we can say then f of x equals f of the opposite of x.
02:01
That's a way to algebraically state that a function is even.
02:06
Now we know that g of x is 1 over f of x.
02:15
And according to the statement above if f of x is equal to f of the opposite of x i could do a substitution and show that g of x is equal to 1 over f of the opposite of x well we also know that g of the opposite of x just by definition is 1 over f of the opposite of x if you just take the function g of x equals 1 over f of x and put the opposite of x in both places.
02:54
Okay, well look at what we have here.
02:56
We have that 1 over f of the opposite of x is equal to g of x, and we also have that 1 over f of the opposite of x is equal to g of the opposite of x.
03:11
So we can substitute and say that g of x is equal to g of the opposite of x.
03:20
And that tells us that g of x is even.
03:27
So we've just proven that if f of x is even, then g of x is even.
03:34
So that part is done.
03:37
Now we go the other direction.
03:38
Part two, prove if g of x is even, then f of x is even.
03:43
So this time our given is that g of x is even.
03:49
What does that mean? an even function, just like before, opposite x coordinates have equal, y coordinates.
03:59
So we can say then g of x equals g of the opposite of x.
04:10
Now what is g of x? g of x is 1 over f of x.
04:21
Well if g of x is equal to g of the opposite of x, then 1 over f of x is also equal to g of the opposite of x.
04:32
But what is g of the opposite of x? by definition we know that g of the opposite of x is 1 over f of the opposite of x just by taking the relationship we had in the beginning and plugging the opposite of x in to both inputs okay once again we can do a substitution we see that g of the opposite of x is equal to 1 over f of x and it's also equal to 1 over f of the opposite of x so that tells us that 1 over f of x of that x is equal to 1 over f of the opposite of x...