00:01
This question has three parts.
00:02
So the first part asks us to write a balanced equation for the reaction.
00:06
So our reactants are diatomic green molecules, which are chlorines, and diatomic red molecules, which are oxygens.
00:17
Our products are going to be three atom molecules, consisting of one red, which is oxygen, and two chlorines, green molecules.
00:30
All right.
00:32
So what's our equation going to look like? well, cl2 plus o2 forms ocl2.
00:42
Now the question is, is this balanced? well, we see that it is not, because we have two oxygens on the left, but only one on the right.
00:50
So what do we do? put a coefficient of two in front of the o .c .l .2 in our products.
00:55
But now, although our oxygens are balanced, right, our chlorines are not.
01:03
Because we have four chlorines on the right and only two on the left.
01:06
So we'll put another coefficient of two.
01:08
In front of the chlorine on the left side, and now everything is balanced.
01:18
So this is our equation.
01:21
For part b, let's identify the limiting reactant.
01:25
Is it chlorine or is it oxygen? well, let's think about it, right? in our reactants, we had three, three of our reds, so three oxygens, but we had four chlorines.
01:40
All right.
01:42
But as you can see here, the ratio of reactants is, 2 to 1, meaning we need 2 chlorines for every 1 oxygen.
01:54
That's 2 to 1.
01:59
As we can see here, if we have 3 oxygens, that means we would expect 6 chlorines, 2 to 1 ratio.
02:14
So therefore, our chlorines are the limiting.
02:25
Cl2 is the limiting...