Question
If $I m, n=\int \cos ^{\mathrm{m}} x \sin n x d x$, then $7 I_{4,3}-4 I_{3,2}=$(A) $-\cos 3 x \cos ^{4} x+C$(B) $\cos 3 x \cos ^{4} x+C$(C) $-\frac{1}{3} \cos 3 x \cos ^{4} x+C$(D) none of these
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We need to find the value of $7I_{4,3}-4I_{3,2}$. Show more…
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