Question
If $i_C=25 e^{-40 t} \mathrm{~A}$, what is the time constant $\tau$ and how long will the transient last?
Step 1
The given current is \( i_C = 25 e^{-40 t} \mathrm{~A} \). This is an exponential decay function, which typically has the form \( i(t) = I_0 e^{-t/\tau} \), where \( I_0 \) is the initial current and \( \tau \) is the time constant. Show more…
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(II) How long does it take for the energy stored in a capacitor in a series $R C$ circuit (Fig. $26-58)$ to reach $75 \%$ of its maximum value? Express answer in terms of the time constant $\tau=R C$ .
The current $i$ amperes flowing in a capacitor at time $t$ seconds is given by $i=8.0\left(1-\mathrm{e}^{\frac{-t}{C R}}\right)$, where the circuit resistance $R$ is $25 \times 10^{3}$ ohms and capacitance $C$ is $16 \times 10^{-6}$ farads. Determine (a) the current $i$ after $0.5$ seconds and (b) the time, to the nearest millisecond, for the current to reach $6.0 \mathrm{~A}$. Sketch the graph of current against time.
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