Question
If in an adiabatic process, the pressure is increased by $2 / 3 \%$, then volume decreases by $\left(\right.$ Assume $\left.\frac{C_{P}}{C_{V}}=\frac{3}{2}\right)$ :(a) $\frac{4}{9} \%$(b) $\frac{2}{3} \%$(c) $4 \%$(d) $\frac{9}{4} \%$
Step 1
Step 1: In an adiabatic process, the pressure and volume are related by the equation $PV^{\gamma} = C$, where $\gamma$ is the ratio of specific heats $C_P/C_V$ and $C$ is a constant. Show more…
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In an adiabatic process wherein pressure is increased by $\frac{2}{3} \%$ if $\frac{C_{p}}{C_{v}}=\frac{3}{2}$, then the volume decreases by about (a) $\frac{4}{9} \%$ (b) $\frac{2}{3} \%$ (c) $4 \%$ (d) $\frac{9}{4} \%$
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Round 1
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio $C_{P} / C_{V}$ for the gas is [2003] (A) $4 / 3$ (B) 2 (C) $5 / 3$ (D) $3 / 2$
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