Question
If, in Fig. 9-6 and in Problem 9.33, $h=2.5 R$, how large a force will the 50 -g bead exert on the wire as it passes through point- $C$ ?
Step 1
We can do this by equating the potential energy at point A to the kinetic energy at point C. The potential energy at point A is given by $mgh$ and the kinetic energy at point C is given by $\frac{1}{2}mv^2$. Equating these two gives us: \[mgh = \frac{1}{2}mv^2\] Show more…
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Refer back to Fig. 9-6. How large must $h$ be (in terms of $R$ ) if the frictionless wire is to exert no force on the bead as it passes through point- $B$ ? Assume the bead is released from rest at $A$.
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One end of a 5.0 -cm-long wire is $1.0 \mathrm{cm}$ above a long wire carrying a 10 A current out of the page, as shown in FIGURE CP3380. The 5.0 -cm-long wire carries a 5.0 A current. (The connecting wires are perpendicular to the page and are not seen.) What is the magnitude of the net force on the $5.0-\mathrm{cm}-$ long wire?(FIGURE CAN'T COPY)
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