If, in the circuit shown in Figure P12.65: vS 1=2.8+0.01 cos(ωt) V vS 2=3.5-0.007 cos

Step 1: Identify the given valuesu000Au002D $v_{S1} u003D 2.8 + 0.01u005Ccos(u005Comega t)$ Vu000Au002D $v_{S2} u003D 3.5 u002D 0.00

Question

If, in the circuit shown in Figure P12.65: $$ \begin{aligned} & v_{S 1}=2.8+0.01 \cos (\omega t) \mathrm{V} \\ & v_{S 2}=3.5-0.007 \cos (\omega t) \mathrm{V} \\ & A_{v 1}=-13 \quad A_{v 2}=10 \quad \omega=4 \mathrm{krad} / \mathrm{s} \end{aligned} $$ determine the: a. Common- and differential-mode input signals. b. Common- and differential-mode gains. c. Common- and differential-mode components of the output voltage. d. Total output voltage. e. Common-mode rejection ratio.

   If, in the circuit shown in Figure P12.65:

$$
\begin{aligned}
& v_{S 1}=2.8+0.01 \cos (\omega t) \mathrm{V} \\
& v_{S 2}=3.5-0.007 \cos (\omega t) \mathrm{V} \\
& A_{v 1}=-13 \quad A_{v 2}=10 \quad \omega=4 \mathrm{krad} / \mathrm{s}
\end{aligned}
$$

determine the:
a. Common- and differential-mode input signals.
b. Common- and differential-mode gains.
c. Common- and differential-mode components of the output voltage.
d. Total output voltage.
e. Common-mode rejection ratio.

Principles and Applications of Electrical Engineering

Giorgio Rizzoni 4th Edition

Chapter 12, Problem 65

Instant Answer

Step 1

8 + 0.01\cos(\omega t)$ V - $v_{S2} = 3.5 - 0.007\cos(\omega t)$ V - $A_{v1} = -13$ - $A_{v2} = 10$ - $\omega = 4$ krad/s Show more…

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If, in the circuit shown in Figure P12.65: $$ \begin{aligned} & v_{S 1}=2.8+0.01 \cos (\omega t) \mathrm{V} \\ & v_{S 2}=3.5-0.007 \cos (\omega t) \mathrm{V} \\ & A_{v 1}=-13 \quad A_{v 2}=10 \quad \omega=4 \mathrm{krad} / \mathrm{s} \end{aligned} $$ determine the: a. Common- and differential-mode input signals. b. Common- and differential-mode gains. c. Common- and differential-mode components of the output voltage. d. Total output voltage. e. Common-mode rejection ratio.

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