Question
If it takes 75.0 min for the concentration of a reactant to drop to $25.0 \%$ of its initial value in a first-order reaction, what is the rate constant for the reaction in the units $\min ^{-1} ?$
Step 1
This means that two half-lives have passed, because after one half-life, the concentration would be 50% of the initial value, and after another half-life, it would be 25% of the initial value. Therefore, one half-life is 75 minutes divided by 2, which is 37.5 Show more…
Show all steps
Your feedback will help us improve your experience
Anthony Han and 54 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If it takes 78.9 min for the concentration of a reactant to drop to 20.0% of its initial value in a first-order reaction, what is the rate constant for the reaction in the units min-1?
It takes $15.4$ minutes for the concentration of a reactant to drop to $5.0 \%$ of its initial value in a second-order reaction. What is the rate constant for the reaction in the units of $\mathrm{L} \mathrm{mol}^{-1} \mathrm{~min}^{-1}$ ?
It takes 15.4 minutes for the concentration of a reactant to drop to $5.0 \%$ of its initial value in a second-order reaction. What is the rate constant for the reaction in the units of $\mathrm{L} \mathrm{mol}^{-1} \min ^{-1}$ ?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD