00:01
So in the given question we are told that there is a matrix which has the determinant.
00:11
The matrix is given as 1 by a, 1 plus a, 1, 1, 1 plus b, 1, 1, 1 plus c.
00:30
So this is the determinant that has been given and it is equal to a, b, c.
00:35
This is what is given in the question.
00:38
And now we are told to find what is the value of 1 by a plus 1 by b plus 1 by c.
00:46
So in order to find the value of this expression, what we do first is we need to simplify the determinant and solve it to find the value just to evaluate the left hand side of this equation.
01:01
Right.
01:02
So let's take this determinant and let's multiply and divide.
01:06
The first row with a the second row with b and the third row with c so on multiplying we would have a b c and on dividing we would have 1 by a plus 1 1 1 by a 1 by a 1 by b 1 by b plus 1 by b and 1 by c plus 1 so this is what we would have so in the next step let's add let's change and let's do a row operation that says that would add r1 plus r2 plus r3 so r1 changes to r1 plus r3 and then we would get the determinant as a bc times 1 by a 1 by b plus 1 by c plus 1 by 1 by a plus 1 by b plus 1 by c plus 1 and 1 by a plus 1 by b plus 1 by c plus 1.
02:25
The rest of the determinant would be the same...