00:01
So, in the given question we have the, there is a determinant of a matrix that is given as x x x y x x x y x x y x y x x and we are told that the value of this determinant.
00:24
If the value of this determinant is equal to 0, then we need to choose from one of the four options that is given in the question.
00:32
So, any one of this option is the correct answer.
00:37
So the first option is given as y equal to x or y equal to minus 2x.
00:46
The second option is given as y equal to x or y equal to 2x.
00:55
The third option is given as y equal to minus x or y equal to minus two times x and the last option option d is given as y equal to minus x or y equal to 2x so these are the options that are given in the christian and the oddly thing that we are told is that the determinant given over here is equal to equal to 0 so what we can do over here is we can simplify this determinant first so let's do a column operation over here changing the first column to c1 plus c2 plus c3 so once we do this the determinant would look like 2x plus y 2x plus y 2x plus y so the first column would change like this and the rest of the matrix is the same.
02:02
The determinant is the same.
02:04
So xyx, y, x, x, and from here we can take 2x plus y as a common factor outside the determinant...