Question
If $l=I \sin \omega t$ and $v=L \frac{\mathrm{df}}{\mathrm{d} t}+R I$, find the mean value of the product $v i$ between $t=0$ and $t=\frac{2 \pi}{4}$
Step 1
Given $i = I \sin \omega t$ and $v = L \frac{df}{dt} + R I$, the product $v i$ is given by: \[v i = (L \frac{df}{dt} + R I) \cdot (I \sin \omega t)\] Show more…
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