00:01
In this problem, we are given a limit that has a solution.
00:05
We know the solution.
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And from there, we need to figure out the solution to two other limits.
00:12
So really what we're dealing with here is beginning to understand how we can use limits across products and quotients of functions.
00:21
And we're going to be talking about that if you're cute.
00:24
Pardon me, if you're confused now, hopefully this will make sense at the end of the video.
00:29
So let's first start out with what we're given.
00:32
We're given the limit as x approach 0 of f of x over x squared, and we know this limit is 1.
00:38
So for part a is saying, well, let's try to find the limit as x approach 0 of f of x.
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This is not the same as the limit before, but can i find this limit knowing that the first one equals 1? and the answer is yes, we can.
00:55
The first thing that we're going to do is we'll distribute this limit, in the numerator and the denominator of our given function.
01:03
So we'll get the limit as x approaches 0 of f of x divided by the limit as x approach 0 of x squared, and we know this equals 1.
01:14
So clearly we can see that if our x is approaching 0, our denominator is going to approach 0 as well.
01:20
What's 0 squared? well that's simply 0.
01:23
So if we rearrange this, we would say the limit as x approaches 0 of f of x equals 1 times 0.
01:30
We just moved this denominator to the other side.
01:35
So clearly we can see that the limit as x approach is 0 of f of x is 0.
01:41
And now on to part b, part b is a very similar procedure...