Question
If lines $\frac{x-1}{-3}=\frac{y-2}{2 k}=\frac{z-3}{2}$ and $\frac{x-1}{3 k}=\frac{y-5}{1}=\frac{z-6}{-5}$ are mutually perpendicular, then $\mathrm{k}$ is equal to-(a) $\frac{-10}{7}$(b) $-\frac{7}{10}$(c) -10(d) -7
Step 1
The first line is given by the equations \(\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}\). The direction ratios for this line can be extracted as \((-3, 2k, 2)\). Show more…
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