00:01
So in the given question we are told that the matrix a, the matrix a is the matrix a is a square matrix, a square matrix of order 3 and it satisfies the equation a cube minus 11a square plus 36a minus 30 i is equal to 0 and now we are told to find an expression for the term a raised to 5 so in the options we can see that in all options the equations have the terms a square a and i so we should find an expression for a raised to 5 such that the expression only contains these terms so that we can choose the correct option from the given question.
01:18
So first let's take the equation and write it as a cube is equal to 11 a square plus 11 a square minus 36a plus 30i and we can say we can take this as equation number one right and now let's multiply a square on both sides of this equation and so on multiplying a square, what we will have us a raised to 5 is equal to 11 a squared to 4 minus 36 a cube plus 30 a square.
01:56
Right.
01:58
And from this we can write, we can take 11a times a cube minus 36 a cube plus 30a squared plus 30a.
02:12
Square and instead of a cube we are going to substitute it with the expression in the equation number one that we just marked so what will happen is we will have 11 a times 11 a square minus 36 a plus 30 i minus 36 a cube plus 30 a square right so in in the next step, what we do is to further simplify this.
02:46
So when we multiply this and simplify the equation, what we will have is we will have 85 a cube minus 366a square plus 330a.
03:06
So this is what we would have after expanding and simplifying the above explanation...