Question
If $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are distinct and positive, and $(2 \mathrm{a}+3 \mathrm{~b}+5 \mathrm{c})^{10}>\lambda \mathrm{a}^{2} \mathrm{~b}^{3} c^{5}$, then $\lambda=$(a) 10(b) $10^{10}$(c) $10^{\prime / 2}$(d) $\frac{1}{10}$
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