00:01
I've given here ab cd is in gp right the first part says that a plus b plus b plus b plus b plus t plus gp we assume that it's in gp if we take here b plus t plus t f f f squared equals a plus b plus b c plus ab plus b c plus b c plus b c plus b c plus b b this we have now i can just work on here, ab cd is in gp, right? so we can take, let's say, a over b equals b over c, equals b over c, equals b over c, equals b over d, equals 1 over k.
00:51
So from here, we'll find out b equals ak, t equals ak square, and d equal akq.
01:02
Let's put the values here, ak in this, and c as ak square, and c, d as akq.
01:07
We'll find out that this left -hand side is equal to right -hand side.
01:11
It's both going to be equal.
01:13
That is only possible when we have a, b, c, d is in g -b.
01:16
If a -b -c -d is in g -b.
01:21
So, option a, here we have.
01:27
So option a is correct.
01:32
If we look at now, option 2, that is, from beginners, ax2 plus c is a factor of, given the qiquilomium, for b -part.
01:47
A x cubed plus b x squared plus d x plus b x squared plus d plus c plus c b over a so to check that a x square plus c is the factor of this this we can write it as a x square plus c times x plus b over a plus d negative c b over a now if we just work on the right side here right hand side will be a x cube plus we get a x square times b over it so bxp plus cx plus you will get c b over a and negative c b over a and plus b certifies you.
02:31
We can write in this way...