Question
If $\mathrm{k}, \mathrm{l}, \mathrm{m}$ and $\mathrm{n}$ are four consecutive integers, then $\mathrm{i}^{\mathrm{k}}+\mathrm{i}^{1}+\mathrm{i}^{\mathrm{m}}+\mathrm{i}^{\mathrm{n}}$ is equal to(a) 1(b) 0(c) 2(d) 4
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This is because we can choose any integer $k$ and the next three integers will be $k+1$, $k+2$, and $k+3$. Show more…
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