Question
If $\mathrm{p}$ is negation of $\mathrm{q}$, then $(\mathrm{p} \Rightarrow \mathrm{q}) \vee(\mathrm{q} \Rightarrow \mathrm{p})$ is $\mathrm{a}$(1) tautology(2) contradiction(3) contingency(4) none of these
Step 1
We can write this as $p = \neg q$. Show more…
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