If $\mathrm{y}=-2$ is a tangent
$\Rightarrow \mathrm{px}^{2}+\mathrm{qx}+\mathrm{r}+2=0 \quad$ will have only one real root
$\Rightarrow \mathrm{q}^{2}-4 \mathrm{p}(\mathrm{r}+2)=0$
$=\mathrm{q}^{2}-4 \mathrm{pr}-8 \mathrm{p}=0$
$\Rightarrow \mathrm{p}<0$ as $\left(\mathrm{q}^{2}-4 \mathrm{pr}<0\right)$
$\Rightarrow \mathrm{r}<0$