00:01
All right, it is given that for the given determinant, your maximum value is alpha, minimum value is beta.
00:06
I want to check the correct relations.
00:08
Let's work on this.
00:11
We can apply first.
00:13
We have c1, it tends to c1 plus c2.
00:16
The determinant is coming out to be 1 plus sine square x plus 4 square x, that is 2.
00:22
This will again give 2.
00:23
This will give 1.
00:25
Next, 4 square x.
00:27
1 plus 4 square x.
00:33
4xxxxx sine 2x sine 2x 1 plus sine 2x this we have got determinant now the next part is we can apply here r2 tends to r2 negative r1 this will become co r2 tends to r2 negative r1 and r3 tends to r3 negative r1 so we have simplifications you get it as determinant that would be the first rodumain as it is sine 2x will be 0, 1, this will be 0, and this will be negative 1, this will be 0, this will be 1.
01:23
If you now expand it, let's say along r2.
01:29
So positive negative, this will be positive, so we get it as 2 plus sine 2x.
01:35
Now sine 2x has the maximum value that is 1, so alpha is coming up to be 3...