For the first population, we have $n_{1}=40$ and $p_{1}^{\prime}=0.9$. We can calculate $q_{1}^{\prime}$ as $1-p_{1}^{\prime}=1-0.9=0.1$. Then, we multiply to get $n_{1}p_{1}^{\prime}=40*0.9=36$ and $n_{1}q_{1}^{\prime}=40*0.1=4$.
For the second population, we
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