00:01
So this question asks us to find what the slope of a tangent line is given by the polar curve, r is equal to 8 sine theta.
00:09
At the point where r is equal to 4 and theta is equal to 5, pi over 6.
00:20
So we want to find out what d .y by d x is, which is also equal to d .y.
00:30
By d -veta, d -d -fator inverse.
00:39
So you need to find out what both of those are, and see what comes out.
00:44
I have a point.
00:46
So y being equal to xan -fater means better.
00:52
We get, what is it? 8 sine squared.
00:59
Now, d -y by d -fater, zer equal to 16 sine -veta -cose -veta, which is equal to, i mean, you don't need to write this.
01:15
So you're 2, 8, sine, 2, theta.
01:21
Alright, now, what is x, x is equal to r, cos theta, which in this case is equal to 8, sine theta, cos theta, which using the trig identity is equal to 4, sine 2 theta.
01:46
I mean, you could have differentiated the product if you want to do this, i guess, makes it easier...