Question
If oxygen is $21 \%$ by mole of air, what is the oxygen state $(P, T, v)$ in a room at $540 \mathrm{R}, 15$ psia of total volume $2000 \mathrm{ft}^{3}$ ?
Step 1
This can be done by multiplying the total pressure by the mole fraction of oxygen. The mole fraction of oxygen is given as $21 \%$ or $0.21$ and the total pressure is $15$ psia. Therefore, the partial pressure of oxygen $P_{o_{2}}$ is given by: \[P_{o_{2}} = 0.21 Show more…
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