00:01
Hi friends here we have to find sear stress at a, v and c given p skull to 15 kilo and diameter of circular cross -section to be 18mm.
00:34
Let us draw the free body diagram.
00:39
Force is acting at a, b and c.
00:43
At c, it would be cx and cy and c.
00:57
At b, by and bx at a, ax and ay.
01:17
Applying the condition of equilibrium at b point.
01:27
Applying condition of equilibrium at b point.
01:44
Moment of force must be 0, that is 15 into 0 .5 minus 60 into 1 .5 minus 60 into 2 minus 30 into 4 .5 that is 3 sorry minus 30 into 4 .5 plus a y into 4 .5 sorry 5 must be 0 so a y you will get 82 .5 kilo newton now summation of f5 must be 0 v .y minus 15 minus 60 minus 60 minus 30 plus a y is equal to 0 so vy you will get 82 .5 kilo now moment of couple about c must be 0 that is 82 .5 cost of 30 minus b x sine of 30 is so bx you will get 142 .9 kilo newton.
03:54
Summission of f5 must be 0, that is minus vy plus cy is equal to 0.
04:06
So cy you will get 82 .5 kilo newton.
04:12
Now submission of fx must be 0, that is minus vx plus cx is equal to 0...