Question
If pH of $0.001 \mathrm{M}$ potassium propionate solution be $8.0$, then the dissociation constant of propionic acid will be(a) $10^{-3}$(b) $10^{-2}$(c) $10^{-2.5}$(d) $10^{-5}$
Step 1
0, we can calculate the pOH using the formula: \[pOH = 14 - pH\] Substituting the given pH value, we get: \[pOH = 14 - 8 = 6\] Show more…
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