00:01
Now we're just going to be looking at the beer -lambut law, and we recall the beir -lambut law to be a equals e -c -l, where all of the units are noted there, and the absorbance is unitless, because they all cancel, as we can see.
00:16
So for the purpose of this question here, we need to rearrange the equation.
00:22
Now, in rearranging it, we're finding the concentration, where we have a over e -l, where we know our absorbance is 0 .735.
00:34
Our length, past length, is 1 centimetre, and our e -value is 50 ,100.
00:43
So plugging those values into the equation up here, this one, taking this equation here, we're plugging the values in, so we've got 0 .735 over 50 ,100, multiplied by 1.
01:00
And that gives us 1 .46 times 10 to the negative 5...