00:01
This question has two parts.
00:01
So the first part is asking us to write down the balanced equation for the reaction.
00:07
So let's take a look at our reactants.
00:10
We have diatomic white molecules.
00:14
These white spheres represent hydrogens.
00:17
Okay, and we have diatonic purple spheres.
00:22
So they represent iodine.
00:24
Let's take a look at our products.
00:28
So essentially across a, b, and c, we see that the products all are just going to be these purple and white spheres.
00:38
So one purple, one white per molecule.
00:40
So it would be h -i.
00:44
And then we see that there's different numbers of them, and then also in product c, we see as well a diatomic iodine.
00:51
But because that same molecule appears in the reactants, we know that it is just simply an excess in that situation.
00:58
So before we can write out the balanced equation, let's kind of deal with these ones right here.
01:03
So how do we write out two h's? well, we'd write it as h2.
01:06
How do we write out two iodines? we'd write it out as i2.
01:14
So how do we write out this balanced equation? well, we simply write down for equation h2 plus i2 produces h -i.
01:29
Now the question is, is this balance? the answer is no, because we have two hydrogens on the left, we only have one on the right.
01:36
So let's put a coefficient of two right in front.
01:40
So now we have two on the left, two on the right...