If $S_{1}$ and $S_{2}$ are surface areas of the solids generated by revolving the ellipees $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ and $\frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1$ about the $y$-axis, then
(a) $S_{1}>S_{j}$
(b) $S_{1}<\mathcal{S}_{2}$
(c) $S_{1}=S_{2}$
(d) can't predict