If spring break when velocity of m2 is (5 v0)/(4) the velocity of other block will be (A) (1)/(4

Name: Problem 114, Chapter 5: A Complete Resource Book in Physics for JEE Main
Uploaded: 2021-11-01T09:59:50-08:00
Duration: 1 min 44 s
Channel: Khoobchandra Agrawal
Description: If spring break when velocity of m2 is (5 v0)/(4) the velocity of other block will be (A) (1)/(4)((m2)/(m1)) v0 (B) (3)/(4)((m2)/(m1)) v0 (C) (1)/(4)((m1)/(m2)) v0 (D) (3)/(4)((m1)/(m2)) v0

step 1 Hi friends here it is given two blocks of mass M1 M2 kept on the smooth surface connected togeth

Question

If spring break when velocity of $m_{2}$ is $\frac{5 v_{0}}{4}$ the velocity of other block will be (A) $\frac{1}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$ (B) $\frac{3}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$ (C) $\frac{1}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$ (D) $\frac{3}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$

   If spring break when velocity of $m_{2}$ is $\frac{5 v_{0}}{4}$ the velocity of other block will be
(A) $\frac{1}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$
(B) $\frac{3}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$
(C) $\frac{1}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$
(D) $\frac{3}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$

A Complete Resource Book in Physics for JEE Main

Sanjeev Kumar 1st Edition

Chapter 5, Problem 114

Instant Answer

Solved by Expert Khoobchandra Agrawal

11/01/2021

Step 1

An initial velocity $v_{0}$ is given to $m_{2}$. The spring breaks when the velocity of $m_{2}$ is $\frac{5v_{0}}{4}$. We need to find the velocity of $m_{1}$ at this point. Show more…

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If spring break when velocity of $m_{2}$ is $\frac{5 v_{0}}{4}$ the velocity of other block will be (A) $\frac{1}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$ (B) $\frac{3}{4}\left(\frac{m_{2}}{m_{1}}\right) v_{0}$ (C) $\frac{1}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$ (D) $\frac{3}{4}\left(\frac{m_{1}}{m_{2}}\right) v_{0}$

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Key Concepts

Conservation of Momentum

This fundamental principle in mechanics states that in an isolated system with no external forces, the total momentum remains constant before and after any interaction. In problems involving interactions such as masses connected by a spring, it allows us to relate the velocities and masses of the blocks at different moments, especially when the spring breaks or releases its stored energy.

Spring-Mass Systems Dynamics

Spring-mass systems are a common study topic in classical mechanics wherein masses are connected by a spring that can store potential energy when compressed or extended. Analyzing these systems typically involves both energy conservation and momentum conservation, particularly at critical points such as when the spring is at maximum extension or breaks, which provides insight into the distribution of energy and momentum between the interacting masses.

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