00:01
So we need to find the value of 10 alpha plus beta in this case.
00:05
So as all option consists of 10 alpha term, so basically first we need to convert this particular thing in 10 so that we can match the option.
00:19
So 10 beta is equal to n sine alpha, cos alpha and upon 1 minus n cos square alpha.
00:32
So in this case, i'm just dividing with cost square alpha term in numerator and denominator so that we can convert it into 10 term.
00:45
So in this case, this cost and this power will cancel out.
00:50
So this will result as n10 alpha upon.
00:55
So 1 upon cost square alpha would be sec square alpha and minus n.
01:01
Now we can convert this sec square alpha in 10, that is n 10 alpha upon 1 plus 10 square alpha minus n.
01:15
Now we can find the value of 10 alpha plus beta as 10 alpha plus beta would be 10 alpha plus 10 beta and whole upon 1 minus 10 alpha and 10 veta.
01:38
So i'm just replacing these values.
01:41
So 10 alpha would be 10 alpha only and this 10 beta would be this term.
01:47
That is n 10 alpha upon 1 minus n plus 10 square alpha and in denominator this would be 1 minus 10 alpha...