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If $\tan \mathrm{A}=\cot \mathrm{B}$, prove that $\mathrm{A}+\mathrm{B}=90^{\circ}$.

Precalculus

Chapter 8

Introduction to Trigonometry

Section 3

Trigonometric Ratios of Some Specific Angles

Trigonometry

Johns Hopkins University

Campbell University

Boston College

Utica College

Lectures

07:16

In mathematics, a continuo…

04:09

01:32

Use the law of cosines to …

01:53

Prove each identity.$$…

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01:16

Prove the identities provi…

02:19

00:44

Prove the identity.$$\…

00:41

If $A$ and $B$ are complem…

02:13

Prove each identity.$$\sin…

02:54

01:06

Prove the identities.$…

01:58

02:11

01:28

If $\sin \alpha+\cos \alph…

01:29

Prove that $\tan \left(180…

02:22

01:42

02:06

PROOF Use the Law of Cos…

Prove the addition formula…

01:30

Show, using the law of cos…

01:10

Show that $\frac{\sin A}{\…

So in the different question we had asked that if 10 of an angle age is equal to court off an angle be, Then we are told to prove that a plus B is equal to 90°,, right? So we have an identity that says that town of an angle can be written as caught off 90 minus eight. Right? So here we can come back to this identity can bear this identity with the expression that we have over here, which is stand is equal to God be. So we can see that we have, we can say 90 minus A. Is then equal to be since the season identity. Right? So we can write 90 minus eight is then equal to be which means we can right, 90 is equal to A plus B. So this is the required relation. That is when we add A and B. We get 90 degrees F. God if 10 A is equal to God be. So if 10 is equal to God be the angles in world, which is A and B would add up to get nine add up to give us 90 degree as the Sun. So I hope you understood the method. Thank you.

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