Question
If the $a$ and $b$ loci are 20 m .u. apart in humans and an $A B / a b$ woman mates with an $a b / a b$ man, what is the probability that their first child will be $A b / a b$ ?
Step 1
The woman has the genotype \( A B / a b \), which means she is heterozygous for both loci. The man has the genotype \( a b / a b \), which means he is homozygous recessive for both loci. Show more…
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If the $a$ and $b$ loci are 20 m.u. apart in humans and an $A B / a b$ woman mates with an $a b / a b$ man, what is the probability that their first child will be $A b / a b ?$
Two linked genes, (A) and (B), are separated by 18 m.u. A man with genotype Aa Bb marries a woman who is aa bb. The man's father was aa bb. What is the probability that their first child will be Aa Bb?
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